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5x^2=150^2
We move all terms to the left:
5x^2-(150^2)=0
We add all the numbers together, and all the variables
5x^2-22500=0
a = 5; b = 0; c = -22500;
Δ = b2-4ac
Δ = 02-4·5·(-22500)
Δ = 450000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{450000}=\sqrt{90000*5}=\sqrt{90000}*\sqrt{5}=300\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-300\sqrt{5}}{2*5}=\frac{0-300\sqrt{5}}{10} =-\frac{300\sqrt{5}}{10} =-30\sqrt{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+300\sqrt{5}}{2*5}=\frac{0+300\sqrt{5}}{10} =\frac{300\sqrt{5}}{10} =30\sqrt{5} $
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